[–] martin-adams 10y ago ↗ I found the following example to be extremely confusing: a = 10 b = 5 > a > 30 When I thought about it after seeing what it compiles to: var a, b; a = 10; b = (5 > a && a > 30); I couldn't see how that statement could be true because a cannot be less than 5 while also be greater than 30.Range checking I would assume would be: b = 5 < a > 30 [–] rec 10y ago ↗ You are absolutely right!The range check would be "`5` is less than `a` and `a` is less than `30`". Meaning that `a` is between 5 and 30.It's fixed now. Thanks martin-adams! [–] martin-adams 10y ago ↗ Glad I could help. And also noticed that you fixed the error in my version as well - ha!
[–] rec 10y ago ↗ You are absolutely right!The range check would be "`5` is less than `a` and `a` is less than `30`". Meaning that `a` is between 5 and 30.It's fixed now. Thanks martin-adams! [–] martin-adams 10y ago ↗ Glad I could help. And also noticed that you fixed the error in my version as well - ha!
[–] martin-adams 10y ago ↗ Glad I could help. And also noticed that you fixed the error in my version as well - ha!
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[ 4.1 ms ] story [ 11.2 ms ] threadRange checking I would assume would be:
The range check would be "`5` is less than `a` and `a` is less than `30`". Meaning that `a` is between 5 and 30.
It's fixed now. Thanks martin-adams!