[–] pascal_cuoq 15y ago ↗ double x0 = 0x1.0000000000001p0; double y = 0x1p-53 * (1. - 0x1p-11); double z1 = x0 + y;or other examples taken from http://hal.archives-ouvertes.fr/docs/00/28/14/29/PDF/floatin... would have been more interesting than 0.1 + 0.2, for which every tested language seem to compute the proper IEEE 754 double precision result.
2 comments
[ 3.2 ms ] story [ 27.7 ms ] threador other examples taken from http://hal.archives-ouvertes.fr/docs/00/28/14/29/PDF/floatin... would have been more interesting than 0.1 + 0.2, for which every tested language seem to compute the proper IEEE 754 double precision result.