[–] direwolf20 5mo ago ↗ All mesh routing protocols suffer from O(N^2) path data and traffic, collapsing at a few thousand nodes.
[–] shetaye 5mo ago ↗ Interesting, the protocol seems to assume symmetrical performance i.e. X-...->Y and Y-...->X will have the same latency so long as they follow the same path?
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