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His last question: "How do I prevent my engineers from performing at 1/10x?"

Did he mean 1/10x, or (1/10)x, or (as I suspect based on the substance of the discussion) did he mean (1/10)(10x) = x ?

You would have thought that a _real_ 10x programmer would not make an operator precedence error like that!

yeah... the conclusion got complicated, but I hope the point remains :)