[–] dalke 12y ago ↗ That was the Pythonic approach until 2006. With Python 2.5 the Pythonic solution was often to use defaultdict: >>> from collections import defaultdict >>> words = ['a', 'the', 'an', 'a', 'an', 'the'] >>> d = defaultdict(int) >>> for word in words: ... d[word] += 1 ... >>> d defaultdict(<type 'int'>, {'a': 2, 'the': 2, 'an': 2}) It's a bit more cumbersome, but the performance is better, and defaultdict(list)[key].append() is much better than setdefault(key, []).append(value).In modern Python (starting with Python 2.7, released in 2010), the Pythonic solution is collections.Counter: >>> from collections import Counter >>> words = ['a', 'the', 'an', 'a', 'an', 'the'] >>> Counter(words) Counter({'a': 2, 'the': 2, 'an': 2}) or dict(Counter(words)) if you want the result to return an actual dict instead of a Counter instance.
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[ 3.7 ms ] story [ 12.6 ms ] threadIn modern Python (starting with Python 2.7, released in 2010), the Pythonic solution is collections.Counter:
or dict(Counter(words)) if you want the result to return an actual dict instead of a Counter instance.