The Paradox of the Black Feminist Panda: Godel and Intersectionality (cultstate.com) 3 points by CultState 11y ago ↗ HN
[–] CultState 11y ago ↗ Let theories be a set of theorems.Let a theorem be a set of proofs that predict and detect oppression.Let intersectionality imply inversions (!) to be:- The intersections (∩) of the complement (c) of a theory with its overlapping theories and non-overlapping theories.- The absolute complement of an theory and all non-overlapping theories.Let intersectionality deny complements of a theory as a complete theory.Let intersectionality treat all intersecting theories as new theories.Let A, C, D be overlapping theories, thus:Let D = B ∩ CLet E = C ∩ ALet F = A ∩ BThus, inversions can be defined as:!A = (A ∩ B)c ∩ C!B = (B ∩ C)c ∩ A!C = (C ∩ A)c ∩ BThus:!A = D !B = E!C = FBut:(A ∩ B)c ∩ C = B ∩ C(B ∩ C)c ∩ A = C ∩ A(C ∩ A)c ∩ B = A ∩ BThis is logically false since B ∩ C contains not just (A ∩ B)c ∩ C, but also A ∩ B ∩ C.Intersectionality's implications of inversion, then, is false.To further demonstrate the point, let X be a different theory of oppression that has no intersecting theorems. Thus:Ø = X ∩ AØ = X ∩ BØ = X ∩ CØ = X ∩ DØ = X ∩ EØ = X ∩ FThus:X ∉ B ∩ CX ∉ C ∩ AX ∉ A ∩ BHowever, due to the second rule of inversion, X is part of all inversions. Thus:!A = DØ = X ∩ DØ = X ∩ (B ∩ C)But:!A = (A ∩ B)c ∩ CØ = X ∩ !AØ = X ∩ (A ∩ B)c ∩ CIs a false statement.
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[ 2.9 ms ] story [ 9.1 ms ] threadLet a theorem be a set of proofs that predict and detect oppression.
Let intersectionality imply inversions (!) to be:
- The intersections (∩) of the complement (c) of a theory with its overlapping theories and non-overlapping theories.
- The absolute complement of an theory and all non-overlapping theories.
Let intersectionality deny complements of a theory as a complete theory.
Let intersectionality treat all intersecting theories as new theories.
Let A, C, D be overlapping theories, thus:
Let D = B ∩ C
Let E = C ∩ A
Let F = A ∩ B
Thus, inversions can be defined as:
!A = (A ∩ B)c ∩ C
!B = (B ∩ C)c ∩ A
!C = (C ∩ A)c ∩ B
Thus:
!A = D !B = E
!C = F
But:
(A ∩ B)c ∩ C = B ∩ C
(B ∩ C)c ∩ A = C ∩ A
(C ∩ A)c ∩ B = A ∩ B
This is logically false since B ∩ C contains not just (A ∩ B)c ∩ C, but also A ∩ B ∩ C.
Intersectionality's implications of inversion, then, is false.
To further demonstrate the point, let X be a different theory of oppression that has no intersecting theorems. Thus:
Ø = X ∩ A
Ø = X ∩ B
Ø = X ∩ C
Ø = X ∩ D
Ø = X ∩ E
Ø = X ∩ F
Thus:
X ∉ B ∩ C
X ∉ C ∩ A
X ∉ A ∩ B
However, due to the second rule of inversion, X is part of all inversions. Thus:
!A = D
Ø = X ∩ D
Ø = X ∩ (B ∩ C)
But:
!A = (A ∩ B)c ∩ C
Ø = X ∩ !A
Ø = X ∩ (A ∩ B)c ∩ C
Is a false statement.