Photons are bosons, thus they don't interact, right? So you can't bounce light off of light to photograph it?
Edit: Okay, so I was being pedantic.
Anyway, if the wave is propagating through a wire, and waves have duration, then aren't you really capturing a picture of a wire propagating an old wave, and a new set of photons acting as particles?
That's like taking a picture of a boiling pot of water and saying you got a picture of water simultaneously as a liquid and a gas, because there is liquid water in the pot and steam rising off of it.
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[ 0.24 ms ] story [ 20.0 ms ] threadIt also seems to not be light, but something similar.
Photons are bosons, thus they don't interact, right? So you can't bounce light off of light to photograph it?
Edit: Okay, so I was being pedantic.
Anyway, if the wave is propagating through a wire, and waves have duration, then aren't you really capturing a picture of a wire propagating an old wave, and a new set of photons acting as particles?
That's like taking a picture of a boiling pot of water and saying you got a picture of water simultaneously as a liquid and a gas, because there is liquid water in the pot and steam rising off of it.