> The classic formula derived from it, n/log(n), is always above the actual number of primes No? pi(100) = 25, but 100 / log(100) = 21.7 The logarithmic integral is larger than pi for "small" arguments. But there is a…
> The classic formula derived from it, n/log(n), is always above the actual number of primes No? pi(100) = 25, but 100 / log(100) = 21.7 The logarithmic integral is larger than pi for "small" arguments. But there is a…