Ok, but then they should explain this particular case better. The RHS can be figured out just by choosing the overloaded operators. In C++ terms, if you have int& operator+(const int&x, const int& y) then (1 + 1) is not…
Ok, but then they should explain this particular case better. The RHS can be figured out just by choosing the overloaded operators. In C++ terms, if you have int& operator+(const int&x, const int& y) then (1 + 1) is not…