> Also, mathematicians agree in this, seriously. Go and ask one. As an erstwhile mathematician, I don't know of anyone who would suggest that -e^(i pi) is defined as 1. It falls out, rather elegantly, from the…
> Also, mathematicians agree in this, seriously. Go and ask one. As an erstwhile mathematician, I don't know of anyone who would suggest that -e^(i pi) is defined as 1. It falls out, rather elegantly, from the…