Re: centers on the octave [2/3, 4/3] but the error is actually more balanced across [1/sqrt(2), sqrt(2)] For the computation of the natural logarithm using binary floating-point arithmetic there is no practical…
Re: centers on the octave [2/3, 4/3] but the error is actually more balanced across [1/sqrt(2), sqrt(2)] For the computation of the natural logarithm using binary floating-point arithmetic there is no practical…