Here is what I tried for (https://leetcode.com/problems/longest-increasing-path-in-a-m...)

INPUT:

Given an m x n integers matrix, return the length of the longest increasing path in matrix.

From each cell, you can either move in four directions: left, right, up, or down. You may not move diagonally or move outside the boundary (i.e., wrap-around is not allowed).

Input: matrix = [[9,9,4],[6,6,8],[2,1,1]] Output: 4 Explanation: The longest increasing path is [1, 2, 6, 9].

class Solution: def longestIncreasingPath(self, matrix: List[List[int]]) -> int:

ChatGPT:

if not matrix or not matrix[0]: return 0

            # initialize the 2D array with all zeros
        dp = [[0] * len(matrix[0]) for _ in range(len(matrix))]
        
        # initialize the result with 0
        result = 0
        
        # iterate through each cell in the matrix
        for i in range(len(matrix)):
            for j in range(len(matrix[0])):
                # perform DFS starting from the current cell
                result = max(result, self.dfs(matrix, dp, i, j))
        
        # return the result
        return result

    # helper function to perform DFS
    def dfs(self, matrix, dp, i, j):
        # if the path length is already calculated, return it
        if dp[i][j] > 0:
            return dp[i][j]
        
        # initialize the path length with 1
        path_len = 1
        
        # check the adjacent cells
        for dx, dy in [(1, 0), (-1, 0), (0, 1), (0, -1)]:
            # get the coordinates of the adjacent cell
            x, y = i + dx, j + dy
            
            # check if the adjacent cell is valid
            if 0 <= x < len(matrix) and 0 <= y < len(matrix[0]):
                # check if the adjacent cell has a smaller value
                if matrix[x][y] > matrix[i][j]:
                    # perform DFS on the adjacent cell and update the path length
                    path_len = max(path_len, 1 + self.dfs(matrix, dp, x, y))
        
        # store the path length in the 2D array
        dp[i][j] = path_len
        
        # return the path length
        return path_len