Because most of the time* an array name decays to a pointer to the first element of the array. So when the array is declared char alphabet[10] = {'a', 'b', 'c', 'd', 'e'}; What the alphabet variable "holds" can be seen…
Because most of the time* an array name decays to a pointer to the first element of the array. So when the array is declared char alphabet[10] = {'a', 'b', 'c', 'd', 'e'}; What the alphabet variable "holds" can be seen…